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Re:太失败了,这么简单的题居然交了13次才通过。

Posted by 123456789987654321 at 2009-04-28 17:05:37 on Problem 1152
In Reply To:太失败了,这么简单的题居然交了13次才通过。 Posted by:link85 at 2007-05-29 00:30:16
> 个人思路:
>   设输入的是abcd,假设其解是n进制,则有
>    (a*n*n*n + b*n*n + c*n + d)%(n-1)=0
> 则有:( (a*n*n*n)%(n-1)+
>         (b*n*n)%(n-1)+
>         (c*n)%(n-1)+
>          d  )%(n-1)=0
> 
> 则有:(  (a* (n%(n-1)) *(n%(n-1)) *(n%(n-1)))+
>           (b* (n%(n-1)) *(n%(n-1)))+
>           (c* (n%(n-1) +
>           d ) %(n-1)=0
> 
> 则有: (a*1*1*1+b*1*1+c*1+d)%(n-1)=0
> 则有:(a+b+c+d)%(n-1)=0
> 
> 所以,经过转换,变为求输入数的各数位的和能%(n-1)等于0;

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