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刚ac得代码,算是费了一点周折,主要是在优化上要下功夫,不然很容易re得。#include<iostream> #include<cmath> using namespace std; int prime[10000]; short judge(long x) { long i; for(i=2;i<=sqrt((double)(x));i++) { if(x%i==0) { return 1; } } return 0; } int main() { long i,j,m=0; for(i=2;i<=32769;i++) { if(judge(i)==0) { prime[m]=i; m++; } } long n; while(cin>>n,n!=0) { int count=0; int len; for(i=0;n>=prime[i];i++); len=i; for(i=0;prime[i]<=n/2;i++) { for(j=len+2;prime[j]>=n/2;j--) { if(prime[i]+prime[j]==n) { count++; break; } } } cout<<count<<endl; } return 0; } Followed by: Post your reply here: |
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