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没有必要用二维数组做，直接考虑循环输出就可以了可以把输入的字符串看做是二维数组，再分作m/n/2次循环输出，每次输出两个上下相邻的数，然后再考虑下m/n%2!=0的情况就可以了，没有必要把它转换成二维数组！ Followed by: Post your reply here: |
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