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Re:tleIn Reply To:tle Posted by:javaman at 2005-01-20 14:19:23 > #include <iostream>
> #include <cstdio>
> #define INF 2000000000
> using namespace std;
>
> int mod[21][21],r[21],tr[21],p,best,lastm,lastr;
>
> void solve(int num,int now) {
> int t,i,ii,j;
>
> if (num>=best) return;
> if (now==0) {
> best=num;
> return;
> }
> t=mod[now][now-1];
> for (i=0;i<p;++i)
> if ((t*i)%p==r[now]) {
> for (j=1;j<now;++j) {
> tr[j]=r[j];
> r[j]=(r[j]-i*mod[j][now-1]%p+p)%p;
> }
> ii=(i==0)?0:1;
> solve(num+ii,now-1);
> for (j=1;j<now;++j)
> r[j]=tr[j];
>
> }
>
> }
>
>
>
>
>
> int main() {
> int n,t1,t2,i,j,k;
> while (true) {
> scanf("%d%d",&n,&p);
> if (!(p+n)) break;
> for (i=1;i<=n;++i) {
> scanf("%d",&r[i]);
> --r[i];
> }
> memset(mod,0,sizeof(mod));
> for (i=1;i<=n;++i) {
> scanf("%d",&j);
> for (;j>0;--j) {
> scanf("%d%d",&t1,&t2);
> mod[i][t1-1]=t2;
> }
> for (j=1;j<i;++j) {
> if (mod[i][j-1]==0) continue;
> t1=mod[j][j-1];
> t2=mod[i][j-1];
> r[i]=((r[i]*t1)%p-(r[j]*t2)%p+p)%p;
> for (k=j;k<n;++k)
> mod[i][k]=((mod[i][k]*t1)%p-(mod[j][k]*t2)%p+p)%p;
> }
> }
> for (lastm=n;lastm>0;--lastm) {
> for (j=lastm-1;j<n;++j)
> if (mod[lastm][j]!=0) break;
> if (j<n) break;
> }
> for (lastr=n;lastr>0;--lastr)
> if (r[lastr]!=0) break;
> best=INF;
> /*for (i=1;i<=n;++i) {
> for (j=0;j<i-1;++j)
> printf(" 0");
> for (j=i-1;j<n;++j)
> printf("%5d",mod[i][j]);
> printf(" =%5d\n",r[i]);
> }
> best=0;
> for (i=n;i>=1;--i) {
> t1=mod[i][i-1];
> for (j=0;j<p;++j)
> if ((t1*j)%p==r[i]) break;
> if (j==p) break;
> if ((r[i]=j)>0) ++best;
> for (j=1;j<i;++j)
> r[j]=(r[j]-r[i]*mod[j][i-1]%p+p)%p;
> }*/
> if (lastm>=lastr)
> solve(0,n);
> if (best==INF) printf("No solution\n");
> else
> printf("%d\n",best);
>
> }
> return 0;
> }
>
>
>
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