#include <stdio.h>
void main()
{
	float xinxi[100000],sum=0;
	long i,shu[1000],n;
	for (i=1;i<100000;i++)
	{
		sum+=1.000000/(2*i);
		xinxi[i]=sum;
	}
	n=0;
	while (scanf("%ld",&shu[n])!=-1)
		n++;
	printf("Cards  Overhang\n");
	for (i=0;i<n;i++)
		printf("%5ld%10.3f\n",shu[i],xinxi[shu[i]]);
}

• 优化后的程序 (248) ferrettemp 2005-01-17 23:55:18
  • float改成double就好了 (278) tide713 2005-05-02 21:40:33
    • 谢谢好心人,当年是多么稚嫩啊... (0) ferret_chao 2005-09-20 23:30:36
    • Re:float改成double就好了 (24) houxuanfelix 2006-07-14 22:41:22
      • 对牌的个数n作归纳，用到杠杆平衡条件 (28) bufan_2001 2006-08-16 19:05:53
        • Re:对牌的个数n作归纳，用到杠杆平衡条件 (23) ccred 2007-08-05 12:37:45
    • Re:float改成double就好了 (9) done 2007-03-09 15:22:15