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我看时间都差不多,估计用的方法也差不多吧。In Reply To:大家讲一下这一题怎么做啊!!!我想了几天,都想不出什么的快捷的算法!!!拜托!!!!谢谢!!! Posted by:acmgotogether at 2006-04-19 21:05:43 #include<stdio.h>
int b[50001][2];
int a[50001];
void dyn(int n)
{
b[0][0]=a[0];
b[0][1]=a[n-1];
int i;
for(i=1;i<n;i++)
if(b[i-1][0]>0)b[i][0]=b[i-1][0]+a[i];
else
b[i][0]=a[i];
for(i=1;i<n;i++)
if(b[i-1][1]>0)b[i][1]=b[i-1][1]+a[n-1-i];
else
b[i][1]=a[n-1-i];
for(i=1;i<n;i++)
if(b[i-1][1]>b[i][1])b[i][1]=b[i-1][1];
}
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
int n;
scanf("%d",&n);
int i,j;
for(i=0;i<n;i++)
scanf("%d",&a[i]);
dyn(n);
int max=-10000001;
int temp;
for(i=0;i<n-1;i++)
{
if(b[i][0]+b[n-2-i][1]>max)max=b[i][0]+b[n-2-i][1];
}
printf("%d\n",max);
}
return 0;
}
能过。
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