def seq(i)
  s = ""
  idx = 1
  sk = ""
  size = 0
  while size < i
    sk << idx.to_s
    size += sk.size
    idx += 1
  end
  #p s
  sk[i - size - 1].chr
end

p seq 2147483647
#=> 2

嘿嘿，玩玩。

• Re:贴个Ruby 的 (1) zhanglongpan 2009-08-20 19:34:43