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Re:通过传递闭包的算法,环都是被求出来的,但是最后我们只累加出度和入度,无礼本身环的存在.真是一道不差的水题,水份刚刚好In Reply To:通过传递闭包的算法,环都是被求出来的,但是最后我们只累加出度和入度,无礼本身环的存在.真是一道不差的水题,水份刚刚好 Posted by:gfedcba at 2009-03-02 21:13:05 > int sum = 0;
> int ans = 0;
> for (i=1; i<=n; i++)
> {
> sum = 0;
> for (j=1; j<=n; j++)
> {
> if (i == j) // 不计算本身环
> {
> continue;
> }
> // 计算出度和入度的总和
> if (matrix[i][j])
> {
> sum++;
> }
> if (matrix[j][i])
> {
> sum++;
> }
> }
> if (sum == n-1)
> {
> ans++;
> }
> }
> cout<<ans<<endl;
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