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这题 cin 超时 scanf 却好用。。。。长知识#include<iostream>
using namespace std;
int main()
{
int n , *num ;
while(cin >> n && n )
{
num = new int[n+1] ;
int i , j ;
for( i = 1 ; i <= n ; i++ )
{
scanf("%d",&num[i]);
}
for( j = 1 ; j <= n ; j++ )
{
if( num[num[j]] != j )
{
break ;
}
}
if( j == n + 1 )
{
cout << "ambiguous" <<endl;
}
else
{
cout << "not ambiguous" << endl;
}
}
return 0 ;
}
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