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Re:解法有二

Posted by daemon85 at 2009-02-24 12:53:57 on Problem 1067
In Reply To:Re:解法有二 Posted by:zhang271417377 at 2008-10-29 19:48:26 
> 
> 受教了
> 
> 先手必输序列推到出来了,但是一直没找到合适的通式
> 
> 
> 3. 一般表达式为（[a·r], [b·r]），其中，a=(sqrt(5)+1)/2，b=(sqrt(5)+3)/2=(sqrt(5)+1)/2+1=a+1
> 4. a与b恰为黄金分割X=(sqrt(5)-1)/2=0.618和 1/X同1之和。即a=1+X，b=1+1/X。
>
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