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Re:这题超级简单,找规律In Reply To:Re:这题超级简单,找规律 Posted by:soligho at 2008-08-23 17:45:28 末尾为1 前一位必为0 ：f(n-2)种 末尾为0 f(n-1) .. Followed by: Post your reply here: |
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