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Re:大家看一下这样的构想对不对In Reply To:Re:大家看一下这样的构想对不对 Posted by:55 at 2009-02-19 13:34:35 > 如果6的位置上是偶数置0 > 如果是奇数置1 > 考虑6=5+1=4+2=4+1+1=3+3=3+2+1=3+1+1+1=2+2+2=2+2+1+1=2+1+1+1+1=1+1+1+1+1+1 > 在分别在各数字对应减去 > 代码如下: > #include<stdio.h> > int f(int t) > { > if(t==0) return 1; > else return 0; > } > int f2(int a,int t) > { > int sum=0; > if(t==0) return f(a%2); > if(a>=2) sum+=f((a-2)%2); > if(sum>=1) return 1; > else return 0; > } > int f3(int a,int b,int t) > { > int sum=0; > if(t==0) return f2(a,b%2); > if(a>=1&&b>=1) sum+=f2(a-1,(b-1)%2); > if(a>=3) sum+=f2(a-3,b%2); > if(sum>=1) return 1; > else return 0; > } > int f4(int a,int b,int c,int t) > { > int sum=0; > if(t==0) return f3(a,b,c%2); > if(a>=1&&c>=1) sum+=f3(a-1,b,(c-1)%2); > if(b>=2) sum+=f3(a,b-2,c%2); > if(a>=2&&b>=1) sum+=f3(a-2,b-1,c%2); > if(a>=4) sum+=f3(a-4,b,c%2); > if(sum>=1) return 1; > else return 0; > } > int f5(int a,int b,int c,int d,int t) > { > int sum=0; > if(t==0) return f4(a,b,c,d%2); > if(a>=1&&d>=1) sum+=f4(a-1,b,c,(d-1)%2); > if(b>=1&&c>=1) sum+=f4(a,b-1,c-1,d%2); > if(a>=2&&c>=1) sum+=f4(a-2,b,c-1,d%2); > if(a>=1&&b>=2) sum+=f4(a-1,b-2,c,d%2); > if(a>=3&&b>=1) sum+=f4(a-3,b-1,c,d%2); > if(a>=5) sum+=f4(a-5,b,c,d%2); > if(sum>=1) return 1; > else return 0; > } > > int f6(int a,int b,int c,int d,int e,int t) > { > int sum=0; > if(t==0) return f5(a,b,c,d,e%2); > if(a>=1&&e>=1) sum+=f5(a-1,b,c,d,(e-1)%2); > if(b>=1&&d>=1) sum+=f5(a,b-1,c,d-1,e%2); > if(a>=2&&d>=1) sum+=f5(a-2,b,c,d-1,e%2); > if(c>=2) sum+=f5(a,b,c-2,d,e%2); > if(a>=1&&b>=1&&c>=1) sum+=f5(a-1,b-1,c-1,d,e%2); > if(a>=3&&c>=1) sum+=f5(a-3,b,c-1,d,e%2); > if(b>=3) sum+=f5(a,b-3,c,d,e%2); > if(a>=2&&b>=2) sum+=f5(a-2,b-2,c,d,e%2); > if(a>=4&&b>=1) sum+=f5(a-4,b-1,c,d,e%2); > if(a>=6) sum+=f5(a-6,b,c,d,e%2); > if(sum>=1) return 1; > else return 0; > } > int main() > { > int a,b,c,d,e,f,t; > __int64 sum; > t=1; > scanf("%d%d%d%d%d%d",&a,&b,&c,&d,&e,&f); > while(1) > { > if(a==0&&b==0&&c==0&&d==0&&e==0&&f==0) break; > sum=a*1+b*2+c*3+d*4+e*5+f*6; > if(sum%2==1) > { > printf("Collection #%d:\n",t++); > printf("Can't be divided.\n\n"); > scanf("%d%d%d%d%d%d",&a,&b,&c,&d,&e,&f); > continue; > } > printf("Collection #%d:\n",t++); > if(f6(a,b,c,d,e,f%2)) printf("Can be divided.\n\n"); > else printf("Can't be divided.\n\n"); > scanf("%d%d%d%d%d%d",&a,&b,&c,&d,&e,&f); > } > return 0; > } Followed by:
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