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本题是很简单的递推

Posted by libojie at 2009-02-20 00:09:06 on Problem 1664
本题是很简单的递推。
①最少的盘子放了一个,这样每个盘子至少一个,n个盘子先放上n个,剩下的m-n个可以随便放
②最少的盘子没有放,这样剩下的n-1个盘子还是随便放m个
int f(int m,int n)
{ if(m<0)
   return 0;
  if(m==0||n==1)
   return 1;
  return f(m-n,n)+f(m,n-1);
}

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