这里G++不支持long long int么?

#include <cstdio>

int main() {
	int t,i,j,k,sign,pos;
	char pn[64],num[64];
	long long int N;
	scanf("%d\n", &t);
	for (i=0; i<t; i++) {
		scanf("%d\n", &k);
		scanf("%s\n", pn);
		scanf("%lld\n", &N);
		pos=0;
		if (N>0) sign=1; else sign=-1;
		for (j=k-1; j>=0; j--) {
			if (pn[j]=='p') {
				num[pos]=sign*(N%2);
				N = (N-num[pos])/2;
				pos++;
			} else {
				num[pos]=sign*(N%2);
				N = (N+num[pos])/2;
				pos++;
			}
		}
		if (N!=0) {printf("Impossible\n"); continue;}
		for (j=pos-1; j>=0; j--) {
			printf("%d",num[j]);
		}
		printf("\n");
	}
}

• Re:偶在ZJU过了, 为什么在这儿WA? (37) hacky 2004-12-24 00:54:55
  • 支持的，只是输入不能用lld，用I64d (41) hawk 2004-12-24 11:29:29