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终于在两年之后寻得了答案。即使退役我也瞑目了。In Reply To:Re:巨挫人求这题的500K左右的代码?谢谢呀~~~~^^^^^^^^不到500 呵呵 Posted by:wangfengtian at 2008-12-14 19:22:23 > #include<stdio.h>
> void main()
> {
> int n,p,m,a[1000]={0},i,k,t,max;
> while(1)
> {
> t=0;
> scanf("%d%d",&n,&p);
> if(n==0&&p==0)
> break;
>
> while(n--)
> {
> scanf("%d",&m);
> while(m--)
> {
> scanf("%d",&k);
> a[k]++;
> }
> }
> for(i=0,max=a[0];i<1000;i++)
> if(a[i]>max)
> {
> max=a[i];
> k=i;
> }
> if(max>=p)
> printf("%d\n",k);
> else
> printf("0\n");
> for(i=0;i<1000;i++)
> a[i]=0;
> }
> }
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