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Re:难道没有人会?

Posted by blackdog at 2008-11-28 22:07:49
In Reply To:大家看看这个问题有没有多项式解法或者有没有公式? Posted by:blackdog at 2008-11-28 22:03:23
> 0-1矩阵
> 考虑n*n矩阵的赋值问题:只能赋0和1,n为偶数,使每一行和列均含n/2个0及n/2个1。 
> 例如,当n=4时,两种可能的方案是: 
> 
> + - - - - + + - - - - + 
> | 0 1 0 1 | | 0 0 1 1 | 
> | 1 0 1 0 | | 0 0 1 1 | 
> | 0 1 0 1 | | 1 1 0 0 | 
> | 1 0 1 0 | | 1 1 0 0 | 
> + - - - - + + - - - - + 
> 
> 问:对于给定n,共有多少种不同的赋值方案。 
> 
> 好像是个面试题目!不会做。不知道有没有公式!
> 大家过来讨论一下
> 

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