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Re:谁来证明一下,次数 k 和 k%8 效果是一样的。In Reply To:谁来证明一下,次数 k 和 k%8 效果是一样的。 Posted by:ohthree at 2004-12-05 12:23:47 > 加上了这个优化,就过了,没想通如何证明。
> 代码如下:
> #include <iostream>
> #include <algorithm>
> #include <vector>
>
> using namespace std;
>
> int main(int argc,char* argv[])
> {
> int i,j,sum;
> bool flag;
> for(int count=1;;count++)
> {
> flag = false;
> vector<int> datapool;
> sum = 0;
> for(i=1;i<=6;i++)
> {
> cin>>j;
> flag = flag || j!=0 ;
>
> j = j % 8; //这里!
> for(;j>0;j--)
> {
> datapool.push_back(i);
> sum += i;
> }
>
> }
> if(!flag)
> break;
> int half = sum /2;
> if(sum % 2 != 0)
> {
> flag = false;
> }
> else
> {
> do
> {
> int partsum = 0;
> for(i=0;i<datapool.size();i++)
> {
> if(partsum==half)
> {
> flag = true;
> break;
> }
> else
> {
> partsum += datapool[i];
> if(partsum>half)
> {
> flag = false;
> break;
> }
> else
> continue;
> }
> }
> if(flag)
> break;
> }while(next_permutation(datapool.begin(),datapool.end()));
> }
> if(flag)
> {
> cout<<"Collection #"<<count<<":"<<endl;
> cout<<"Can be divided."<<endl<<endl;
> }
> else
> {
> cout<<"Collection #"<<count<<":"<<endl;
> cout<<"Can't be divided."<<endl<<endl;
> }
> }
> }
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