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哪位能提供些测试数据啊,我用并查集做的,交上去老是WA,代码如下:如发现问题请指正#include <iostream>
#include <algorithm>
#include <math.h>
using namespace std;
int n, m, k, num1, num2, sum;
int i, j, t;
int used[104][104], parent[104][104], rank[104][104];
//建立一个节点 ,由于每个节点的位置都不同故可以用i*10+j来记录其位置
void makeset(int i, int j)
{
parent[i][j] = i*10 + j;
used[i][j] = true;
rank[i][j] = 1;
}
//寻找该点所在根节点,并压缩路径
int findset(int i, int j)
{
int t;
int tempi =i, tempj = j;
while( tempi*10 + tempj != parent[tempi][tempj] )
{
t = parent[tempi][tempj];
tempi = t/10;
tempj = t%10;
}
while( i*10 + j != tempi*10 + tempj)
{
t = parent[i][j];
parent[i][j] = tempi*10 +tempj;
i = t/10;
j = t%10;
}
return tempi*10 + tempj;
}
//合并两棵树,这里用rank[i][j]来记录根的地位并同时用其代表水坑的坑数
void unionset(int i, int j, int i1,int j1 )
{
int t = findset(i, j);
int tep;//暂时变量
i = t/10; j = t%10;
t = findset(i1, j1);
i1 = t/10; j1 = t%10;
if( i == i1&& j == j1)
return ;
if( rank[i][j]>rank[i1][j1] )
{
parent[i1][j1] = parent[i][j];
rank[i][j] += rank[i1][j1];
tep = rank[i][j];
}
else
{
parent[i][j] = parent[i1][j1];
rank[i1][j1] += rank[i][j];
tep = rank[i1][j1];
}
if( tep > sum)
sum = tep;
}
int main()
{
while (cin>>n>>m>>k)
{
memset(used , 0, sizeof(used));
sum = 1;
for( i = 0; i < 101; i++)
for(j = 0; j < 101; j++)
rank[i][j] = 1;
for( i = 1; i <= k ; i++)
{
cin>>num1>>num2;
if(used[num1][num2])//如果坑已经输入了,就continue;
continue;
makeset(num1, num2);
if(used[num1-1][num2])//以下四个用于找该点4周的树,若有,合并
unionset(num1-1 , num2, num1, num2);
if(used[num1+1][num2])
unionset(num1+1, num2, num1, num2);
if(used[num1][num2-1])
unionset(num1,num2-1, num1, num2);
if(used[num1][num2+1])
unionset(num1, num2+1, num1, num2);
}
cout<<sum<<endl;
}
return 0;
}
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