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Faint!!!水到一种境界了。。。题目说的是必须要翻k次。
如果n是偶数，分成两个奇数（即，正的奇数个，反的奇数个）那么必要翻奇数次
分成两个偶数，必要翻偶数次。故无解
如果n是奇数，只能分成一奇一偶，显然翻n-1次就行了（n-1为偶数，我们只翻偶数那种的）
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