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判断数组是否满足条件的函数aint filter(int p[],int n)
{
int i,point=0,temp=p[0];
for(i=1;i<n;i++)
{
if(p[i]!=temp) {temp=p[i];point++;}
}
if(point<=2) return 1;
else return 0;
}
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