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你这代码竟然真能过……看来题目的描述有问题的说In Reply To:此题与2479不是一回事 Posted by:kurtcq at 2008-10-03 20:31:54 > 这道题题目描述与2479几乎一样,但从ac的代码来看根本不是一回事。首先2593网上贴出的ac代码连2479的sample input都不能过。从网上ac的代码来推测本题意图发现此题是一个毫无意义的水题(有些水题还是有些意义的)。 > 下面是我ac的代码(从我代码可以清晰看出本题实际意图) > #include <iostream> > #include <stdio.h> > using namespace std; > int cmp ( const void *a , const void *b ) > { > return *(int *)b - *(int *)a; > } > int main() > { > int sum,n,flag,i,a[100010]; > while (1) > { > sum=0; > flag=0; > scanf("%d",&n); > if (n==0) > break; > for (i=0;i<n;i++) > { > scanf("%d",&a[i]); > if (a[i]>0) > { > flag++; > sum+=a[i]; > } > } > if (flag==0||flag==1) > { > qsort(a,n,sizeof(a[0]),cmp); > printf("%d\n",a[0]+a[1]); > } > else printf("%d\n",sum); > } > return 0; > } Followed by:
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