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nail-biting WA//每一行看至少有一个白格,从每一列看有且仅有一个白格被射中
//也就是说为每一行匹配一个列,其余的列随意指定
#include <iostream>
using namespace std;
#define M 1010
int r,c;
bool used[M],square[M][M];
int link[M];
int white[M]; //每列有两个白格,记录其中一个的行标,以便最后随意指定未匹配列的行标
//对于匹配了的列,记录对应的行标
void Initial()
{
memset( square, 0, sizeof(square) );
memset( link, -1, sizeof(link) );
}
void In()
{
cin>>r>>c;
for(int i=1; i<=c; i++){
int j1,j2;
scanf("%d%d", &j1,&j2);
square[j1][i] = square[j2][i] = true;
white[i] = j1;
}
}
int find(int t)
{
for(int i=1; i<=c; i++){
if( !used[i] && square[t][i] ){
used[i] = true;
if( link[i]==-1 ){
link[i] = t;
return i;
}
int temp = find( link[i] );
if( temp )
return temp;
}
}
return 0;
}
void solve()
{
int cnt=0;
for(int i=1; i<=r; i++){
memset( used, 0, sizeof(used) );
int temp = find(i);
if( temp ){
white[ temp ] = i;
++cnt;
}
}
if(cnt==r){
for(int i=1; i<=r; i++)
printf("%d ", white[i]);
printf("\n");
}
else
printf("NO\n");
}
int main()
{
int Case;
cin>>Case;
while(Case--){
Initial();
In();
solve();
}
return 0;
}
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