 |
| ||||
Home Page
F.A.Qs
Statistical Charts
Past Contests
Scheduled Contests
Award Contest
| ||||||||||
| Online Judge | Problem Set | Authors | Online Contests | User | ||||||
|---|---|---|---|---|---|---|---|---|---|---|
| Web Board Home Page F.A.Qs Statistical Charts | Current Contest Past Contests Scheduled Contests Award Contest | |||||||||
我的推导过程1/a = (1/b + 1/c)/ (1 - 1/(b*c))
=> bc-1 = a(b+c)
assume b=a+m and c=a+n (b and c is always bigger than a)
(a+m)(a+n)-1=a(a+m+a+n)
=> a*a+a*n+a*m+m*n-1=2*a*a+m*a+n*a
=> m*n=a*a+1
and then
for(m=a;m>=1;m--)
if((a*a+1)%m==0)
break;
n=(a*a+1)/m
Followed by:
Post your reply here: |
All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator
