#include<stdio.h>
void main()
{
	int i,m,p[10001]={0},s=1;
	for(i=1;i<10001;i++)
	{
		s*=i;	
		while(1)
		{
			if(s%10==0) s/=10;
			else if(s>100000) s%=100000;
			else	break;
		}
	p[i]=s%10;
	} 
	for(;;)
	{
	scanf("%d",&m);
	printf("%5d -> %d\n",m,p[m]);
	}
}

• Re:output limit exceed ??????怎么回事？ (145) PastForever 2009-08-05 12:23:17