Online JudgeProblem SetAuthorsOnline ContestsUser
Web Board
Home Page
F.A.Qs
Statistical Charts
Problems
Submit Problem
Online Status
Prob.ID:
Register
Update your info
Authors ranklist
Current Contest
Past Contests
Scheduled Contests
Award Contest
User ID:
Password:
  Register
Language:
Keeps Going and Going and ...
Time Limit: 1000MSMemory Limit: 10000K
Total Submissions: 108Accepted: 51

Description

Lazy functional languages like Haskell and Miranda support features that are not found in other programming languages, including infinite lists. Consider the following simple (and useful) recursive declaration:
letrec
count n = cons n (count (n+1))
in
count 0

The function cons constructs lists, so the above declaration creates the following structure:

cons 0 (count 1)
= cons 0 (cons 1 (count 2))
= cons 0 (cons 1 (cons 2 ...))
= [0,1,2,...]

Lazy languages can do this because they only evaluate expressions that are actually used. If a program creates an infinite list and only looks at items 2 and 3 in it, the values in positions 0 and 1 are never evaluated and the list structure is only evaluated so far as the fourth node.

It is also possible to use more than one function to build an infinite list. Here is a declaration that creates the list ["even","odd","even",...]:

letrec
even = cons "even" odd
odd = cons "odd" even
in
even

There are also functions that manipulate infinite lists. The functions take and drop can be used to remove elements from the start of the list, returning the (removed) front elements or the remainder of the list, respectively. Another useful function is zip, which combines two lists like the slider on a zipper combines the teeth. For example,

zip (count 0) (count 10) = [0,10,1,11,2,12,...]

Your task is to implement a subset of this functionality.

Input

The first line of input consists of two positive integers, n and m. n is the number of declarations to follow and m is the number of test cases.

Each declaration takes the form name = expr. There are two forms for expr : zip name1 name2 and x0 x1 ... xi name3. In the first case, name is the result of zipping name1 and name2 together. The other case defines the first i + 1 non-negative integers in the list name (where i is at least 0) and name3 is the name of the list that continues it (mandatory--all lists will be infinite).

The test cases take the form name s e, where s and e are non-negative integers, s <= e and e - s < 250.

No line of input will be longer than 80 characters. Names consist of a single capital letter.

Output

For each test case, print the integers in positions s to e of the list name. List elements are numbered starting with 0.

Sample Input

5 3
S = 4 3 2 1 A
O = 1 O
E = 0 E
A = zip E O
Z = zip Z S
A 43455436 43455438
S 2 5
Z 1 10

Sample Output

0 1 0
2 1 0 1
4 4 3 4 2 3 1 4 0 2

Source

[Submit]   [Go Back]   [Status]   [Discuss]

Home Page   Go Back  To top


All Rights Reserved 2003-2013 Ying Fuchen,Xu Pengcheng,Xie Di
Any problem, Please Contact Administrator